Solve the problem.
-In a lottery, players must pick 6 different numbers from 1 to 22 . How many ways are there to choose the 6 numbers if order is important?
A) 74,613
B) $53,721,360$
C) $113,379,904$
D) 132

Question

Quizplus · Accepted Answer

When order is important, we use permutations. The number of permutations of 6 numbers from a set of 22 is calculated as $ \frac{22!}{(22-6)!} = \frac{22!}{16!} = 53,721,360 $.

Solve the Problem 53,721,36053,721,36053,721,360 C) 113,379,904113,379,904113,379,904 D) 132

Solve the Problem $53,721,360$ C) $113,379,904$ D) 132