Solve the problem.
-A gumball machine had 4 red and 5 yellow gumballs left. You put in pennies until you empty the machine. How many different sequences of red and yellow gumballs can come out of the machine?
A) 15,120
B) 126
C) 131
D) 14

Question

Quizplus · Accepted Answer

The problem is a combinatorial one where we need to find the number of different sequences of 4 red and 5 yellow gumballs. This is a classic "stars and bars" problem, where we calculate the number of ways to arrange 4 red and 5 yellow gumballs. The formula for this is the binomial coefficient C(n, k) = n! / (k!(n-k)!), where n is the total number of gumballs (4+5=9) and k is the number of one type of gumball (either 4 or 5). So, C(9, 4) = 126.

Solve the Problem. -A Gumball Machine Had 4 Red and 5 Yellow Gumballs