Find the largest open intervals where the function is concave upward.
-$f(x)=x^{3}-3 x^{2}-4 x+5$
A) $(-\infty, 1),(1, \infty)$
B) $(1, \infty)$
C) $(-\infty, 1)$
D) None

Question

Quizplus · Accepted Answer

The function is concave upward where its second derivative is positive. The second derivative of $f(x)$ is $f''(x) = 6x - 6$. Setting $f''(x) > 0$ gives $x > 1$, so the interval is $(1, \infty)$.

Find the Largest Open Intervals Where the Function Is Concave f(x)=x3−3x2−4x+5f(x)=x^{3}-3 x^{2}-4 x+5f(x)=x3−3x2−4x+5

Find the Largest Open Intervals Where the Function Is Concave $f(x)=x^{3}-3 x^{2}-4 x+5$