According to the following reaction,how much energy is required to decompose 59.0 kg of Fe₃O₄? The molar mass of Fe₃O₄is 231.55 g/mol.
Fe₃O₄(s) → 3 Fe(s) + 2 O₂(g) ΔH°_rxn= +1118 kJ

Question

According to the following reaction,how much energy is required to decompose 59.0 kg of Fe₃O₄? The molar mass of Fe₃O₄is 231.55 g/mol. Fe₃O₄(s)→ 3 Fe(s)+ 2 O₂(g)ΔH°_rxn= +1118 kJ

Quizplus · Accepted Answer

To find the energy required, first convert 59.0 kg of Fe₃O₄ to moles: 59,000 g / 231.55 g/mol = 254.8 mol. The reaction requires 1118 kJ per mole of Fe₃O₄, so multiply the moles by the enthalpy change: 254.8 mol × 1118 kJ/mol = 2.85 × 10⁵ kJ.

According to the Following Reaction,how Much Energy Is Required to Decompose