A reaction has a rate constant of 5.5 × 10^-2 M^-1s^-1.If you start with an initial concentration of 3.82M,what is the half-life?

Question

Quizplus · Accepted Answer

The reaction is second-order because the rate constant has units of M^-1s^-1. The half-life for a second-order reaction is given by t_1/2 = 1 / (k[A]₀), where k is the rate constant and [A]₀ is the initial concentration. Substituting the given values, t_1/2 = 1 / (5.5 × 10^-2 M^-1s^-1 × 3.82 M) = 4.76 s.

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