At a certain temperature the equilibrium constant,K_c,equals 0.11 for the reaction: 2 ICl(g) ⇌ I₂(g) + Cl₂(g) .
What is the equilibrium concentration of ICl if 0.55 mol of I₂ and 0.55 mol of Cl₂ are initially mixed in a 2.0-L flask?

Question

Quizplus · Accepted Answer

The equilibrium constant expression is:K_c = [I₂][Cl₂]/[ICl]²Substituting the given values:0.11 = (0.55 mol/L)(0.55 mol/L)/[ICl]²Solving for [ICl]:[ICl] = 0.33 M

At a Certain Temperature the Equilibrium Constant,Kc,equals 0

At a Certain Temperature the Equilibrium Constant,K_c,equals 0