The gas OF₂ can be produced from the electrolysis of an aqueous solution of KF,as shown in the equation below. OF₂(g) + 2 H⁺(aq) + 4 e^- → H₂O(l) + 2 F^-(aq) E° = +2.15 V
Using the given standard reduction potential,calculate the amount of OF₂ that is produced,and the electrode at which the OF₂ is produced,upon the passage of 0.0600 faradays through an aqueous KF solution.

Question

Quizplus · Accepted Answer

The reaction shows that 4 moles of electrons produce 1 mole of OF2. 0.0600 faradays correspond to 0.0600 moles of electrons. Therefore, 0.0600/4 = 0.015 moles of OF2 are produced. The molar mass of OF2 is 54 g/mol, so 0.015 moles correspond to 0.810 g. Since OF2 is produced at the anode, the correct answer is 0.810 g at the anode.

The Gas OF2 Can Be Produced from the Electrolysis of an Aqueous

The Gas OF₂ Can Be Produced from the Electrolysis of an Aqueous