Given the following rate law,how does the rate of reaction change if the concentration of X is halved and the concentration of Y is doubled?
Rate = k [X][Y]²

Question

Given the following rate law,how does the rate of reaction change if the concentration of X is halved and the concentration of Y is doubled? Rate = k [X][Y]²

Quizplus · Accepted Answer

Halving [X] decreases the rate by a factor of 2, while doubling [Y] increases the rate by a factor of 4 (since [Y] is squared). Overall, the rate increases by a factor of 2 (4/2 = 2).

Given the Following Rate Law,how Does the Rate of Reaction