A 1000-kg car is moving at 30 m/s around a horizontal unbanked curve whose diameter is 0.20 km.What is the magnitude of the friction force required to keep the car from sliding?

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Quizplus · Accepted Answer

The friction force required to keep the car from sliding can be calculated using the formula for centripetal force, $F = \frac{mv^2}{r}$, where $m$ is the mass of the car, $v$ is the velocity, and $r$ is the radius of the curve. The diameter of the curve is given as 0.20 km, which is 200 meters, so the radius $r$ is half of that, 100 meters. Plugging in the values, $F = \frac{(1000 \, \text{kg})(30 \, \text{m/s})^2}{100 \, \text{m}} = 9000 \, \text{N}$.

A 1000-Kg Car Is Moving at 30 M/s Around a Horizontal