A 50.0-kg crate is being pulled along a horizontal smooth surface.The pulling force is 10.0 N and is directed 20.0° above the horizontal.What is the magnitude of the acceleration of the crate?

Question

Quizplus · Accepted Answer

The horizontal component of the force, which is responsible for the acceleration, is calculated as $F \cos(\theta) = 10.0 \cos(20.0^\circ)$. The mass of the crate is 50.0 kg. Using Newton's second law, $a = \frac{F}{m}$, the acceleration $a$ can be found by substituting the horizontal force and the mass. The correct calculation leads to an acceleration of approximately 0.188 m/s$^2$, making option B the correct answer.

A 500-Kg Crate Is Being Pulled Along a Horizontal Smooth Surface