The primary coil of an ideal transformer has 100 turns and its secondary coil has 400 turns.If the ac voltage applied to the primary coil is 120 V,what voltage is present in its secondary coil?
A)100 V
B)30 V
C)70 V
D)480 V
E)400 V

Question

Quizplus · Accepted Answer

The voltage in the secondary coil can be found using the transformer equation $V_s = V_p \times \frac{N_s}{N_p}$, where $V_s$ is the secondary voltage, $V_p$ is the primary voltage, $N_s$ is the number of turns in the secondary coil, and $N_p$ is the number of turns in the primary coil. Plugging in the given values: $V_s = 120V \times \frac{400}{100} = 480V$.

The Primary Coil of an Ideal Transformer Has 100 Turns