An IgE antibody exposed to the endoproteolytic enzyme pepsin, followed by exposure to the endoproteolytic enzyme papain, will result in which structure in which order?

Question

Quizplus · Accepted Answer

Exposure to pepsin will cleave the IgE antibody into two fragments, F(ab')₂ and Fc. Exposure to papain will then cleave the F(ab')₂ fragment into two F(ab) fragments, leaving the Fc and F(ab')₂ intact. Therefore, the resulting structure will be Fc and F(ab')₂ followed by 2 F(ab).

An IgE Antibody Exposed to the Endoproteolytic Enzyme Pepsin, Followed