How many moles of water, H₂O,are present in 75.0 g H₂O?

Question

Quizplus · Accepted Answer

To determine the moles of H₂O in 75.0 g, we need to use its molar mass: H₂O: H = 1.008 x 1 = 1.008 g/mol, S = 32.06 x 2 = 64.12 g/mol, O = 15.9994 x 1 = 15.9994 g/mol, total molar mass = 1.008 + 64.12 + 15.9994 = 81.1274 g/mol Now we can use the formula: moles = mass/molar mass moles = 75.0 g / 81.1274 g/mol moles = 0.925 moles = 4.16 moles (rounded to two significant figures) Therefore, the answer is B.

How Many Moles of Water, H2O,are Present in 75

How Many Moles of Water, H₂O,are Present in 75