Here is an Excel ANOVA table that summarizes the results of an experiment to assess the effects of ambient noise level and plant location on worker productivity. The test used ? = 0.05. $$\begin{array} { | l | c | c | c | c | c | c | }
\hline \text { Source of Variation } & \text { SS } & d f & M S & F & P \text {-value } & F \text { crit } \
\hline \text { Plant location } & 3.0075 & 3 & 1.0025 & 2.561 & 0.1199 & 3.862 \
\hline \text { Noise level } & 8.4075 & 3 & 2.8025 & 7.160 & 0.0093 & 3.863 \
\hline \text { Error } & 3.5225 & 9 & 0.3914 & & & \
\hline \text { Total } & 14.9375 & & & & & \
\hline
\end{array}$$ The sample size is:
A)15.
B)10.
C)16.
D)impossible to determine.

Question

Here is an Excel ANOVA table that summarizes the results of an experiment to assess the effects of ambient noise level and plant location on worker productivity. The test used ? = 0.05. $$\begin{array} { | l | c | c | c | c | c | c | } 
\hline \text { Source of Variation } & \text { SS } & d f & M S & F & P \text {-value } & F \text { crit } \
\hline \text { Plant location } & 3.0075 & 3 & 1.0025 & 2.561 & 0.1199 & 3.862 \
\hline \text { Noise level } & 8.4075 & 3 & 2.8025 & 7.160 & 0.0093 & 3.863 \
\hline \text { Error } & 3.5225 & 9 & 0.3914 & & & \
\hline \text { Total } & 14.9375 & & & & & \
\hline
\end{array}$$ The sample size is:
A)15.
B)10.
C)16.
D)impossible to determine.

Quizplus · Accepted Answer

The sample size can be determined by adding the degrees of freedom (df) for all sources of variation plus one. Here, $df_{\text{Plant location}} = 3$, $df_{\text{Noise level}} = 3$, and $df_{\text{Error}} = 9$. Thus, the total sample size is $3 + 3 + 9 + 1 = 16$.

Here Is an Excel ANOVA Table That Summarizes the Results