A Cable Is 5 $\times$ 10¹⁰ N/m²

A cable is 5.00 m long and has a diameter of 1.50 mm.The tensile modulus of the cable is 2.50 $\times$ 10¹⁰ N/m².A force is applied to the end of the cable and the cable stretches by 3.00 mm.What is the applied force?

A) 16.5 N
B) 20.5 N
C) 26.5 N
D) 32.6 N
E) 36.6 N