A 4.00 kg ball is moving at 4.00 m/s to the EAST and a 6.00 kg ball is moving at 3.00 m/s to the NORTH.The total momentum of the system is
A) 14.2 kg m/s at an angle of 48.4 degrees SOUTH of EAST.
B) 48.2 kg m/s at an angle of 24.2 degrees SOUTH of EAST.
C) 48.2 kg m/s at an angle of 48.4 degrees NORTH of EAST.
D) 24.1 kg m/s at an angle of 24.2 degrees SOUTH of EAST.
E) 24.1 kg m/s at an angles of 48.4 degrees NORTH of EAST.

Question

Quizplus · Accepted Answer

The total momentum is calculated by vector addition of the momentum of each ball. The momentum of the 4.00 kg ball is 16.0 kg m/s EAST, and the momentum of the 6.00 kg ball is 18.0 kg m/s NORTH. The magnitude of the total momentum is √(16^2 + 18^2) = 24.1 kg m/s. The angle θ with respect to EAST is given by tan⁻¹(18/16) = 48.4 degrees, NORTH of EAST.

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