An ant crawls in a straight line at a constant speed of 0.24 m/s for a distance of 3.0 m,beginning in the corner of a square classroom.It then turns exactly 90 degrees to the right,and proceeds an additional 4.00 m,reaching the far corner of the same wall from which it began.If the second leg was also crawled in half the amount of time as required for the first leg,what was the ant's average speed for the whole trip?
A) 0.80 m/s
B) 0.27 m/s
C) 0.37 m/s
D) 0.44 m/s

Question

Quizplus · Accepted Answer

First, we need to find the time it took the ant to crawl the first leg:
time = distance / speed
time = 3.0 m / 0.24 m/s = 12.5 s

Next, we know that the second leg took half the time of the first leg, so it took:
6.25 s

Now we can find the total distance travelled by the ant:
total distance = 3.0 m + 4.0 m = 7.0 m

And we can find the total time taken by the ant:
total time = 12.5 s + 6.25 s = 18.75 s

Finally, we can find the average speed of the ant for the entire trip:
average speed = total distance / total time
average speed = 7.0 m / 18.75 s = 0.37 m/s

Therefore, the best choice is C, 0.37 m/s.

An Ant Crawls in a Straight Line at a Constant