The isotope of iodine with mass number 128 undergoes beta decay with a half-life of 25.00 minutes. The balanced nuclear reaction for this process is: ${ }_{53}^{128} I \rightarrow{ }_{52}^{128} \mathrm{Te}+{ }_{-1}^{0} \beta$

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The Answer of The isotope of iodine with mass number 128 undergoes beta decay with a half-life of 25.00 minutes. The balanced nuclear reaction for this process is: ${ }_{53}^{128} I \rightarrow{ }_{52}^{128} \mathrm{Te}+{ }_{-1}^{0} \beta$

The Isotope of Iodine with Mass Number 128 Undergoes Beta 53128I→52128Te+−10β{ }_{53}^{128} I \rightarrow{ }_{52}^{128} \mathrm{Te}+{ }_{-1}^{0} \beta53128​I→52128​Te+−10​β

The Isotope of Iodine with Mass Number 128 Undergoes Beta ${ }_{53}^{128} I \rightarrow{ }_{52}^{128} \mathrm{Te}+{ }_{-1}^{0} \beta$