A ball is thrown at an angle of 60^$\circ$ with a velocity of 25 m/s. How much of this velocity is vertical (y) and how much is horizontal (x)?

Question

Quizplus · Accepted Answer

The velocity components can be found using trigonometry: $v_x = v \cos(\theta)$ and $v_y = v \sin(\theta)$, where $v = 25$ m/s and $\theta = 60^\circ$. Thus, $v_x = 25 \cos(60^\circ) = 12.5$ m/s and $v_y = 25 \sin(60^\circ) \approx 21.65$ m/s.

A Ball Is Thrown at an Angle of 60 ∘\circ∘ with a Velocity of 25 M/s

A Ball Is Thrown at an Angle of 60^$\circ$ with a Velocity of 25 M/s