How much energy is required to raise the temperature of 200.0 g of water by 25.0°C? The specific heat of water = 4.184 J g^-1 °C^-1.

Question

Quizplus · Accepted Answer

The formula to calculate the energy required to raise the temperature of a substance is:

q = m × c × ΔT

where 
q = energy required (in Joules)
m = mass of the substance (in grams) 
c = specific heat capacity of the substance 
ΔT = change in temperature (in °C)

Substituting the given values:

m = 200.0 g 
ΔT = 25.0 °C 
c = 4.184 J g^-1 °C^-1

q = 200.0 g × 4.184 J g^-1 °C^-1 × 25.0 °C 
q = 20,900
q = 20.9 kJ

Therefore, the amount of energy required to raise the temperature of 200.0 g of water by 25.0 °C is 20.9 kJ. The correct answer is A).

How Much Energy Is Required to Raise the Temperature of 200.0