A 25.00 mL sample of HCl solution is neutralized by exactly 31.22 mL of 0.08152 M Ca(OH)₂. What is the molarity of the HCl solution?

Question

Quizplus · Accepted Answer

The balanced equation is 2HCl + Ca(OH)2 → CaCl2 + 2H2O. Moles of Ca(OH)2 = 0.03122 L * 0.08152 mol/L = 0.002545 mol. Since 2 moles of HCl react with 1 mole of Ca(OH)2, moles of HCl = 2 * 0.002545 mol = 0.00509 mol. Molarity of HCl = 0.00509 mol / 0.025 L = 0.2036 M.

A 2500 ML Sample of HCl Solution Is Neutralized by Exactly