A 25.00 mL sample of HCl solution is neutralized by exactly 41.63 mL of 0.1363 M NaOH. What is the molarity of the HCl solution?

Question

Quizplus · Accepted Answer

The neutralization reaction between HCl and NaOH is 1:1. Using the formula M1V1 = M2V2, where M1 and V1 are the molarity and volume of HCl, and M2 and V2 are the molarity and volume of NaOH, we find M1 = (0.1363 M * 41.63 mL) / 25.00 mL = 0.2270 M.

A 2500 ML Sample of HCl Solution Is Neutralized by Exactly