At 400 K,an equilibrium mixture of H₂,I₂,and HI consists of 0.025 mol H₂,0.067 mol I₂,and 0 mol HI in a 3.50-L flask.What is the value of K_p for the following equilibrium? (R = 0.0821 L ∙ atm/(K ∙ mol) )
2HI(g) H₂(g) + I₂(g)

Question

At 400 K,an equilibrium mixture of H₂,I₂,and HI consists of 0.025 mol H₂,0.067 mol I₂,and 0 mol HI in a 3.50-L flask.What is the value of K_p for the following equilibrium? (R = 0.0821 L ∙ atm/(K ∙ mol) )
2HI(g)

At 400 K,an equilibrium mixture of H<sub>2</sub>,I<sub>2</sub>,and HI consists of 0.025 mol H<sub>2</sub>,0.067 mol I<sub>2</sub>,and 0 mol HI in a 3.50-L flask.What is the value of K<sub>p</sub> for the following equilibrium? (R = 0.0821 L ∙ atm/(K ∙ mol) ) 2HI(g) H<sub>2</sub>(g) + I<sub>2</sub>(g) A) 0 B) 15 C) 2 D) 45 E) 3

H₂(g) + I₂(g)

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The Answer of At 400 K,an equilibrium mixture of H₂,I₂,and HI consists of 0.025 mol H₂,0.067 mol I₂,and 0 mol HI in a 3.50-L flask.What is the value of K_p for the following equilibrium? (R = 0.0821 L ∙ atm/(K ∙ mol)) 2HI(g) H₂(g)+ I₂(g)

At 400 K,an Equilibrium Mixture of H2,I2,and HI Consists of 0.025

At 400 K,an Equilibrium Mixture of H₂,I₂,and HI Consists of 0.025