Using a normal curve table,if a person has a score of 4.78 on a test,which equals a Z score of 1.5,the percentage of cases that lie above this score is
A)43.32% − 50% = -6.68%
B)50% − 43.32% = 6.68%
C)100% − 43.32% = 56.68%
D)50% + 43.32% = 93.32%

Question

Quizplus · Accepted Answer

Using a normal curve table, we can find that a Z score of 1.5 corresponds to a percentage of 93.32% that lies below that score. Therefore, to find the percentage of cases that lie above the score of 4.78, we subtract 93.32% from 100%, which gives 6.68% (Option B).

Using a Normal Curve Table,if a Person Has a Score