When a drag strip vehicle reaches a velocity of 63 m/s,it begins a negative acceleration by releasing a drag chute and applying its brakes.While reducing its velocity back to zero,its acceleration along a straight line path is a constant −7.2 m/s².What displacement does it undergo during this deceleration period? A) 552 m B) 4 m C) 1,985 m D) 276 m E) 9 m

Question

Quizplus · Accepted Answer

Using the equation $ v^2 = u^2 + 2as $, where $ v = 0 $, $ u = 63 \, \text{m/s} $, and $ a = -7.2 \, \text{m/s}^2 $, we find $ s = \frac{63^2}{2 \times 7.2} = 276 \, \text{m} $.

When a Drag Strip Vehicle Reaches a Velocity of 63