Question 1

When the reflection of an object is seen in a concave mirror the image will:

Accepted Answer

The image formed by a concave mirror can be real or virtual depending on the position of the object relative to the mirror. If the object is located beyond the focal point, the image will be real, inverted and diminished. If the object is located between the focal point and the mirror, the image will be virtual, upright and magnified. Therefore, the image may be either real or virtual. The size of the image will also depend on the distance between the object and the mirror.

Question 2

A container is filled with fluid 1 and the apparent depth of the fluid is 5 cm.The container is next filled with fluid 2,and the apparent depth of this fluid is 3 cm.What is the ratio of the indices of refraction of these fluids?

Accepted Answer

The apparent depth of a fluid is given by:
apparent depth = actual depth / refractive index of fluid
Let's assume the actual depths of fluid 1 and 2 are h1 and h2 respectively. Then we have:
5 = h1/n1     ...(1)
3 = h2/n2     ...(2)
Dividing (1) by (2), we get:
5/3 = (h1/n1)/(h2/n2)
Simplifying, we get:
n1/n2 = 5/3

Question 3

A girl is standing in front of a concave mirror.Consider two rays of light,one from her nose and one from her mouth that are parallel as they are traveling toward the mirror.These rays will come together:

Accepted Answer

In a concave mirror, the rays of light that are parallel to the principal axis converge at a point on the principal axis called the focal point. Therefore, the two parallel rays from the girl's nose and mouth will also converge at the focal point if they are reflected by a concave mirror.

Question 4

An object is placed 10 cm in front of a mirror,and an image is formed that has a magnification of 2.Which of the following statements is true?

Accepted Answer

The answer of An object is placed 10 cm in...

Question 5

Ron fills a beaker with glycerin (n = 1.473)to a depth of 3.0 cm.If he looks straight down through the glycerin surface,he will perceive the liquid to be what apparent depth?

Accepted Answer

The apparent depth can be calculated using the formula: apparent depth = real depth / refractive index. Here, apparent depth = 3.0 cm / 1.473 ≈ 2.0 cm.

Question 6

An object 6 cm high is placed 18 cm in front of a mirror.What type of mirror and what radius of curvature is needed for an image that is upright and 16 cm tall?

Accepted Answer

The image is upright and taller than the object, so the mirror must be concave. The magnification is 16 cm / 6 cm = 2.67. The object distance is 18 cm. Using the thin lens equation, 1/f = 1/do + 1/di, we get f = 9 cm. The radius of curvature is R = 2f = 18 cm.

Question 7

A goldfish is swimming in water (n = 1.33)inside a spherical plastic bowl of index of refraction 1.33.If the goldfish is 12 cm from the front wall of the 23-cm radius bowl,where does the goldfish appear to an observer in front of the bowl?

Accepted Answer

The answer of A goldfish is swimming in water (n...

Question 8

A candle is 55.0 cm in front of a convex spherical mirror of radius of curvature 56.0 cm.What are the image distance and the magnification,respectively?

Accepted Answer

Using the mirror equation: 
1/f = 1/do + 1/di 
Where f is the focal length (equals to half of the radius of curvature for a spherical mirror), do is the object distance, and di is the image distance. 
Rearranging the equation: 
1/di = 1/f - 1/do 
1/di = 1/28 - 1/55 
di = -18.6 cm 
The negative sign indicates that the image is virtual and upright. 
To find the magnification: 
m = -di/do 
m = -(-18.6)/55 
m = 0.337 
The positive magnification indicates that the image is upright. 
Therefore, the correct answer is A) -18.6 cm, +0.337.

Question 9

A 2.5 cm tall object is placed along the principal axis of a thin convex lens of 16 cm focal length.If the object distance is 29 cm,which of the following best describes the image distance and height,respectively?

Accepted Answer

Using the lens formula (1/f = 1/v - 1/u) and magnification formula (m = -v/u = h'/h), the image distance (v) is calculated to be approximately 36 cm, and the image height (h') is approximately 3.1 cm.

Question 10

If atmospheric refraction did not occur,how would the apparent time of sunrise and sunset be changed?

Accepted Answer

Atmospheric refraction causes the sun to appear higher in the sky, which results in an earlier sunrise and a later sunset. If atmospheric refraction did not occur, the opposite would happen, and the sunrise would be later, while the sunset would be earlier. Therefore, the best choice is C, which states that sunrise would be later, and sunset would be earlier.

Question 11

A glass block,for which n = 1.52,has a blemish located 5.0 cm from one surface.At what distance from that surface does the image of the blemish appear to the outside observer?

Accepted Answer

The apparent depth of the blemish is given by the formula: apparent depth = real depth / refractive index. So, 5.0 cm / 1.52 ≈ 3.3 cm.

Question 12

When the reflection of an object is seen in a convex mirror the image will:

Accepted Answer

When the reflection of an object is seen in a convex mirror, the image will always be virtual, which means it cannot be projected onto a screen. The image will also be smaller than the actual object, and not necessarily enlarged.

Question 13

An object is 16.0 cm from the surface of a spherical Christmas tree ornament that is 8.00 cm in diameter.What is the magnification of the image?

Accepted Answer

The answer of An object is 16.0 cm from the...

Question 14

Parallel rays of light that hit a concave mirror will come together:

Accepted Answer

Parallel rays of light that hit a concave mirror will converge (come together) at the focal point.

Question 15

A solid glass sphere with a radius of 8.00 cm and index of refraction of 1.50 has a small coin embedded 2.50 cm from the front surface of the sphere.For the viewer looking at the coin through the glass,at what distance from the front surface of the glass does the coin's image appear to be located?

Accepted Answer

The image of the coin appears to be located 1.86 cm from the front surface of the glass. This is because the index of refraction of glass is greater than that of air, so the light rays from the coin are bent towards the normal when they enter the glass. This causes the image of the coin to appear closer to the front surface of the glass than the coin actually is.

Question 16

An object of length 3.00 cm is inside a plastic block with index of refraction 1.40.If the object is viewed through the top surface of the block at a non-zero angle from the normal,where is the object relative to its image?

Accepted Answer

When an object is viewed through the top surface of a block at a non-zero angle, its image appears to be shifted downward from the actual position of the object. This is because the light rays from the object refract when they enter and exit the block, causing them to bend away from the normal. Since the plastic block has an index of refraction of 1.40, the amount of bending is greater than it would be in air, which means the image appears even lower. Therefore, the object is located above the direction of its image.

Question 17

An object of length 3.20 cm is inside a plastic block with index of refraction 1.30.If the object is viewed from directly above,what is the length of its image?

Accepted Answer

The answer of An object of length 3.20 cm is...

Question 18

Atmospheric refraction of light rays is responsible for:

Accepted Answer

Atmospheric refraction can cause the bending of light rays, which can create mirages (such as seeing a pool of water on the road during hot weather, when there is actually no water present). Spherical aberration, chromatic aberration, and light scattering are not directly caused by atmospheric refraction.

Question 19

A container is filled with fluid 1,and the apparent depth of the fluid is 8.00 cm.The container is next filled with fluid 2,and the apparent depth of this fluid is 6.00 cm.If the index of refraction of the first fluid is 1.30,what is the index of refraction of the second fluid?

Accepted Answer

The index of refraction of a fluid is inversely proportional to the apparent depth of the fluid. Therefore, the index of refraction of the second fluid is 8.00 cm / 6.00 cm * 1.30 = 1.73.

Question 20

An object is placed 10 cm in front of a mirror,and an image is formed that has a magnification of 2.Which of the following statements is false?

Accepted Answer

The other statements are true based on the given information. The focal length can be calculated using the magnification formula (m = -di/do = hi/ho) which gives f = do(m+1)/m = 20 cm. The magnification being 2 means that the image is larger than the object, and since it is formed behind the mirror, it is a virtual image. Therefore, statement D is false because more than one statement is true.

Quiz 23: Mirrors and Lenses