Light with a wavelength of 450 nm shines through a lens with an aperture diameter of 0.85 cm.Use Rayleigh's criterion to determine the limiting angle of resolution.(1 nm = 10−⁹ m) A) 6.5 × 10−⁵ rad B) 1.3 × 10−⁴ rad C) 9.2 × 10−⁵ rad D) 3.0 × 10−⁹ rad

Question

Quizplus · Accepted Answer

Rayleigh's criterion states that the limiting angle of resolution is given by:$$	heta = 1.22 \frac{\lambda}{D}$$where $\lambda$ is the wavelength of light and $D$ is the diameter of the aperture. Plugging in the given values, we get:$$	heta = 1.22 \frac{450 	imes 10^{-9} 	ext{ m}}{0.85 	imes 10^{-2} 	ext{ m}} = 6.5 	imes 10^{-5} 	ext{ rad}$$

Light with a Wavelength of 450 Nm Shines Through a Lens