If the probability distribution of X is:
$$\begin{array} { c c }
\mathrm { X } & \mathrm { P } ( \mathrm { X } ) \
3 & 1 / 8 \
4 & 1 / 8 \
5 & 3 / 8 \
6 & 3 / 8
\end{array}$$
-What is the expected value of X?
A)1
B)2
C)3
D)4
E)5

Question

If the probability distribution of X is:
$$\begin{array} { c c } 
\mathrm { X } & \mathrm { P } ( \mathrm { X } ) \
3 & 1 / 8 \
4 & 1 / 8 \
5 & 3 / 8 \
6 & 3 / 8
\end{array}$$
-What is the expected value of X?
A)1
B)2
C)3
D)4
E)5

Quizplus · Accepted Answer

The expected value (E) of X is calculated by summing the products of each value of X and its corresponding probability: E(X) = (3)(1/8) + (4)(1/8) + (5)(3/8) + (6)(3/8) = 3/8 + 4/8 + 15/8 + 18/8 = 40/8 = 5.

If the Probability Distribution of X Is XP(X)31/841/853/863/8\begin{array} { c c } \mathrm { X } & \mathrm { P } ( \mathrm { X } ) \\3 & 1 / 8 \\4 & 1 / 8 \\5 & 3 / 8 \\6 & 3 / 8\end{array}X3456​P(X)1/81/83/83/8​

If the Probability Distribution of X Is $\begin{array} { c c } \mathrm { X } & \mathrm { P } ( \mathrm { X } ) \\3 & 1 / 8 \\4 & 1 / 8 \\5 & 3 / 8 \\6 & 3 / 8\end{array}$