The "escape velocity" from Earth (the speed required to escape Earth's gravity)is 2.5 × 10⁴ miles per hour.What is this speed in m/s? (1 mile = 1609 m) A)4.2 × 10^-3 m/s B)6.9 m/s C)4.2 × 10² m/s D)1.1 × 10⁴ m/s E)4.0 × 10⁷ m/s

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Quizplus · Accepted Answer

To convert miles per hour to meters per second, multiply by 1609 (meters per mile) and divide by 3600 (seconds per hour). Thus, 2.5 × 10^4 miles/hour × 1609 m/mile ÷ 3600 s/hour ≈ 1.1 × 10^4 m/s.

The "Escape Velocity" from Earth (The Speed Required to Escape