The K_sp for silver(I)phosphate is 1.8 × 10^-18.Calculate the molar solubility of silver(I)phosphate.

Question

Quizplus · Accepted Answer

The dissolution of silver(I) phosphate, Ag₃PO₄, can be represented as: Ag₃PO₄(s) ⇌ 3Ag⁺(aq) + PO₄³⁻(aq). The Ksp expression is: Ksp = [Ag⁺]³[PO₄³⁻]. Let the molar solubility be 's'. Then, [Ag⁺] = 3s and [PO₄³⁻] = s. Substituting these into the Ksp expression gives: Ksp = (3s)³(s) = 27s⁴. Solving 27s⁴ = 1.8 × 10⁻¹⁸ gives s ≈ 1.6 × 10⁻⁵ M.

The Ksp for Silver(I)phosphate Is 1

The K_sp for Silver(I)phosphate Is 1