The rate constant for the first-order decomposition of C₄H₈ at 500°C is 9.2  10^-3 s^-1.How long will it take for 10.0% of a 0.100 M sample of C₄H₈ to decompose at 500°C?

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The Answer of The rate constant for the first-order decomposition of C₄H₈ at 500°C is 9.2  10^-3 s^-1.How long will it take for 10.0% of a 0.100 M sample of C₄H₈ to decompose at 500°C?

The Rate Constant for the First-Order Decomposition of C4H8 at 500°C

The Rate Constant for the First-Order Decomposition of C₄H₈ at 500°C