Sodium borohydride, NaBH4, is a strong reducing agent because ________.
A) Na+ is easily reduced to Na (s)
B) boron easily changes its oxidation number from +3 to -3
C) boron is readily oxidized from -3 oxidation state to +3
D) hydrogen can be easily oxidized from -1 oxidation state to +1
E) hydrogen is easily reduced from +1 oxidation state to 0
Correct Answer:
Verified
Q61: Hydrogen can form hydride ions.Elements in group
Q63: B2O3 is the anhydride of _.
A)borous acid
B)diborane
C)tetraboric
Q67: The primary commercial use of nitric acid
Q68: Soda-lime glass contains _.
A)SiO2 and aluminum
B)SiO2, CaO,
Q68: Which of the following equations correctly represents
Q70: A borane is a _.
A)compound containing only
Q71: The most common isotope of hydrogen is
Q72: Hydrogen can have oxidation states of _.
A)+1
Q72: Boron can violate the octet rule in
Q77: Which one of the following is true
Unlock this Answer For Free Now!
View this answer and more for free by performing one of the following actions
Scan the QR code to install the App and get 2 free unlocks
Unlock quizzes for free by uploading documents