A 3.82-g sample of magnesium nitride is reacted with 7.73 g of water: Mg₃N₂ + 3H₂O → 2NH₃ + 3MgO
The yield of MgO is 3.60 g. What is the percent yield in the reaction?

Question

A 3.82-g sample of magnesium nitride is reacted with 7.73 g of water: Mg₃N₂ + 3H₂O → 2NH₃ + 3MgO The yield of MgO is 3.60 g. What is the percent yield in the reaction?

Quizplus · Accepted Answer

To calculate the percent yield, we need to divide the actual yield by the theoretical yield (based on the stoichiometry of the reaction) and multiply by 100. The stoichiometry of the reaction tells us that 1 mole of Mg₃N produces 3 moles of MgO. So, we need to first calculate the theoretical yield of MgO: 3.82 g Mg₃N₂ x (3 mol MgO/1 mol Mg₃N) x (40.31 g MgO/mol) = 4.58 g MgO Now we can calculate the percent yield: % yield = (actual yield/theoretical yield) x 100 % yield = (3.60 g MgO/4.58 g MgO) x 100 % yield = 78.4% Therefore, the best choice is B.

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