A 36.3 mL aliquot of 0.0529 M H₂SO₄ (aq)is to be titrated with 0.0411 M NaOH (aq). What volume (mL)of base will it take to reach the equivalence point? A)93.4 B)46.7 C)187 D)1.92 E)3.84

Question

Quizplus · Accepted Answer

The balanced equation is H2SO4 + 2NaOH → Na2SO4 + 2H2O. The moles of H2SO4 are 36.3 mL * 0.0529 M = 0.00192 mol. Since the ratio is 1:2, moles of NaOH needed are 0.00384 mol. Volume of NaOH = 0.00384 mol / 0.0411 M = 93.4 mL.

A 363 ML Aliquot of 0