A potential difference of 120 V is established between two parallel metal plates. The magnitude of the charge on each plate is 0.020 C. What is the capacitance of this capacitor?

Question

Quizplus · Accepted Answer

Capacitance is given by C = Q/V, where Q is the charge on each plate and V is the potential difference between the plates. Substituting the given values, we get C = 0.020 C / 120 V = 170 µF.

A Potential Difference of 120 V Is Established Between Two