For a body emitting blackbody radiation,the total power emitted is proportional to the 4th power of the body's absolute temperature: (T in kelvins)
and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to: ( in meters,T in kelvins)
Assume an object is emitting blackbody radiation.
-A body in a room at 300 K is heated to 3,000 K.The amount of energy radiated each second by the body increases by a factor of

Question

For a body emitting blackbody radiation,the total power emitted is proportional to the 4th power of the body's absolute temperature:  (T in kelvins)
and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to:  (  in meters,T in kelvins)
Assume an object is emitting blackbody radiation.
-A body in a room at 300 K is heated to 3,000 K.The amount of energy radiated each second by the body increases by a factor of

Quizplus · Accepted Answer

According to Stefan-Boltzmann law, the power emitted by a blackbody is proportional to the fourth power of its absolute temperature. So, the ratio of power emitted at 3,000 K to that emitted at 300 K is (3000/300)^4 = 10^4. Therefore, the amount of energy radiated each second by the body increases by a factor of 10,000, which is option D.

For a Body Emitting Blackbody Radiation,the Total Power Emitted Is