A 400.0g sample of water is at 30.0^º C.How many joules of energy are required to raise the temperature of the water to 45.0^º C? A)628 J B)1880 J C)25100 J D)450 J

Question

Quizplus · Accepted Answer

The specific heat capacity of water is 4.184 J/g°C.
The formula to calculate the amount of energy required to raise the temperature of a substance is: 
Q = m * c * ΔT
Where Q is the amount of energy in Joules, m is the mass of the substance in grams, c is the specific heat capacity of the substance in J/g°C, and ΔT is the change in temperature in °C.
Using the given values:
m = 400.0g
c = 4.184 J/g°C
ΔT = 45.0°C - 30.0°C = 15.0°C
Q = 400.0g * 4.184 J/g°C * 15.0°C = 25100 J
Therefore, the correct answer is C) 25100 J.

A 4000g Sample of Water Is at 30