The specific heat of zinc is 0.388 J/g^ºC.A 700.0g sample of zinc at 35.0^ºC absorbs 2.336 kJ of heat.What is the final temperature of the zinc? A)8.6^ºC B)26.4^ºC C)43.6^ºC D)301^ºC

Question

Quizplus · Accepted Answer

We can use the formula:

q = m*c*ΔT

where q is the heat absorbed, m is the mass of the substance, c is the specific heat, and ΔT is the change in temperature.

Rearranging, we get:

ΔT = q/(m*c)

Substituting the given values, we get:

ΔT = (2.336 kJ)/(700.0g * 0.388 J/gºC) = 8.61ºC

Therefore, the final temperature of the zinc is:

35.0ºC + 8.61ºC = 43.6ºC

Thus, the answer is C.

The Specific Heat of Zinc Is 0