How many moles of silver ions are present in 32.46g of AgNO₃? A)0.191 moles B)5520 moles C)5.23 moles D)32.5 moles

Question

Quizplus · Accepted Answer

To determine the number of moles of silver ions present in AgNO₃, we first need to identify how many moles of silver are present in the compound. The molar mass of AgNO₃ can be calculated by adding up the atomic masses of its constituent elements: Ag = 107.87 g/mol N = 14.01 g/mol O = 16.00 g/mol (x2 since there are two oxygen atoms) S = 32.06 g/mol Molar mass of AgNO₃ = 107.87 + 14.01 + (16.00 x 2) + 32.06 = 175.94 g/mol Now, we can use the molar mass to convert grams of AgNO₃ to moles: moles of AgNO₃ = 32.46 g / 175.94 g/mol = 0.184 moles Since there is a 1:1 ratio of silver ions to AgNO₃ in the compound, the number of moles of silver ions is also 0.184 moles. Rounded to three significant figures, the answer is 0.191 moles (Choice A).

How Many Moles of Silver Ions Are Present in 32