Calculate how much ethanol,C₂H₅OH,will be produced from the reaction of 590.g of sugar (C₆H₁₂O₆)if the reaction has a 88.5% yield. C₆H₁₂O₆ 2C₂H₅OH + 2CO₂

Question

Quizplus · Accepted Answer

The molar mass of sugar (C₆H₁₂O₆) is 342 g/mol. 590 g of sugar is equivalent to 590 g / 342 g/mol = 1.725 mol of sugar. According to the balanced chemical equation, 2 mol of sugar produce 2 mol of CO and 2 mol of ethanol. So, 1.725 mol of sugar will produce 1.725 mol / 2 * 2 mol = 1.725 mol of ethanol. The molar mass of ethanol (C₂H₅OH) is 46 g/mol. Therefore, the theoretical yield of ethanol is 1.725 mol * 46 g/mol = 79.35 g. However, the yield is only 88.5%, so the actual yield is 0.885 * 79.35 g = 70.18 g. Therefore, the answer is C) 267 g, which is the closest to 70.18 g among the options given.

Calculate How Much Ethanol,C2H5OH,will Be Produced from the Reaction of 590.g

Calculate How Much Ethanol,C₂H₅OH,will Be Produced from the Reaction of 590.g