What volume of ammonia is produced when 0.500 mole of nitrogen reacts completely in the following equation?
N₂(g) + 3 H₂(g) $\rarr$ 2NH₃(g)

Question

What volume of ammonia is produced when 0.500 mole of nitrogen reacts completely in the following equation? N₂(g)+ 3 H₂(g)$\rarr$2NH₃(g)

Quizplus · Accepted Answer

According to the balanced equation, 1 mole of N2 produces 2 moles of NH3. Therefore, 0.500 mole of N2 will produce 1.00 mole of NH3. At STP, 1 mole of any gas occupies 22.4 L. Therefore, 1.00 mole of NH3 will occupy 22.4 L.

What Volume of Ammonia Is Produced When 0 →\rarr→ 2NH3(g) A)1

What Volume of Ammonia Is Produced When 0 $\rarr$ 2NH₃(g)
A)1