What amount of heat is required to convert 3.00 kg of water at its boiling point to steam? The heat of vaporization of water is 2.26 kJ/g.

Question

Quizplus · Accepted Answer

The amount of heat required can be calculated using the formula:
Q = m x Hvap
where Q is the heat required, m is the mass of water being converted, and Hvap is the heat of vaporization of water.
Substituting the given values, we get:
Q = 3.00 kg x 2.26 kJ/g x 1000 g/kg
Q = 6780 kJ
Hence, the answer is option B (6780 kJ).

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