AgNO₃ is added to a saturated AgI solution until the [Ag⁺¹] is 0.050 M.What is the [I^-1] remaining in the solution? The Ksp of AgI is 8.3 10^-17.

Question

Quizplus · Accepted Answer

First, we can write the balanced equation for the dissolution of AgI: AgI (s) ⇌ Ag⁺¹ (aq) + I^-1 (aq) The Ksp expression for AgI is: Ksp = [Ag⁺¹][I^-1] We are given that [Ag⁺¹] = 0.050 M, and we can use the Ksp to solve for [I^-1]: Ksp = 8.3 11ea7f51_1ea5_9d08_9ecd_b78630365fa4_TB4036_11 10^-17 = (0.050 M) x [I^-1] Solving for [I^-1], we get: [I^-1] = Ksp / [Ag⁺¹] = (8.3 11ea7f51_1ea5_9d08_9ecd_b78630365fa4_TB4036_11 10^-17) / (0.050 M) Calculating this, we get: [I^-1] = 1.7 11ea7f51_1ea5_9d0a_9ecd_7fd5a8b1a6dc_TB4036_11 10^-15 M Therefore, the correct answer is C.

AgNO3 Is Added to a Saturated AgI Solution Until the [Ag+1]

AgNO₃ Is Added to a Saturated AgI Solution Until the [Ag⁺¹]