A European sports car dealer claims that his product will accelerate at a constant rate from rest to a speed of 100 km/h in 6.00 s.What distance will the sports car travel during the 6.00-s acceleration period? (Hint: First convert speed to m/s. )

Question

Quizplus · Accepted Answer

First, we need to convert the final speed to m/s:

100 km/h = 27.8 m/s

Using the kinematic equation:

d = (1/2)at^2

Where:
d = distance
a = acceleration
t = time

We can solve for the distance:

d = (1/2)(a)(t^2)

Since the sports car accelerates at a constant rate, we can use the formula:

a = (vf - vi)/t

Where:
vf = final velocity
vi = initial velocity (which is 0, since the car starts from rest)

a = (27.8 m/s - 0 m/s)/6 s
a = 4.63 m/s^2

Substituting into the first formula:

d = (1/2)(4.63 m/s^2)(6 s)^2
d = 83.3 m

Therefore, the distance the sports car travels during the 6.00-s acceleration period is 83.3 meters.

A European Sports Car Dealer Claims That His Product Will