In x-ray machines,electrons are subjected to electric fields as great as 6.0 × 10⁵ N/C.Find an electron's acceleration in this field.(m_e = 9.11 × 10−³¹ kg,e = 1.6 × 10−¹⁹ C) A)1.1E+17 m/s² B)3.4E+13 m/s² C)8.7E+10 m/s² D)2.9E+8 m/s² E)4.1E+13 m/s²

Question

Quizplus · Accepted Answer

The acceleration of an electron in an electric field is given by $a = \frac{F}{m}$, where $F = eE$ is the force on the electron, $e$ is the charge of the electron, $E$ is the electric field, and $m$ is the mass of the electron. Substituting the given values, $a = \frac{(1.6 \times 10^{-19} \, \text{C}) \times (6.0 \times 10^{15} \, \text{N/C})}{9.11 \times 10^{-31} \, \text{kg}} = 1.05 \times 10^{17} \, \text{m/s}^2$, which rounds to $1.1 \times 10^{17} \, \text{m/s}^2$.

In X-Ray Machines,electrons Are Subjected to Electric Fields as Great