If a light bulb has half the resistance of a 110-W light bulb,what would be its wattage? Assume both bulbs are attached to the same 160-V circuit.
A)220 W
B)55 W
C)1.5 W
D)330 W
E)More information is needed.

Question

Quizplus · Accepted Answer

The power (P) of a light bulb in a circuit is given by the formula $P = \frac{V^2}{R}$, where $V$ is the voltage and $R$ is the resistance. If the second bulb has half the resistance of the first, its power would be doubled (since resistance is in the denominator), making it 220 W.

If a Light Bulb Has Half the Resistance of a 110-W