A current-carrying wire of length 52.0 cm is positioned perpendicular to a uniform magnetic field.If the current is 15.0 A and it is determined that there is a resultant force of 2.3 N on the wire due to the interaction of the current and field,what is the magnetic field strength?

Question

Quizplus · Accepted Answer

The magnetic force on a current-carrying wire is given by $F = BIL$, where $F$ is the force, $B$ is the magnetic field strength, $I$ is the current, and $L$ is the length of the wire. Rearranging for $B$, we get $B = \frac{F}{IL}$. Substituting the given values, $B = \frac{2.3\,N}{15.0\,A \times 0.52\,m} = 0.29\,T$.

A Current-Carrying Wire of Length 52