A 420-turn circular coil with an area of 0.0650 m² is mounted on a rotating frame,which turns at a rate of 22.3 rad/s in the presence of a 0.0550-T uniform magnetic field that is perpendicular to the axis of rotation.What is the instantaneous emf in the coil at the moment that the normal to its plane is perpendicular to the field? A)33.5 V B)zero C)0.0673 V D)747 V E)1.50 V

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Quizplus · Accepted Answer

The instantaneous emf in the coil is given by:$$\varepsilon = -N\frac{d\Phi_B}{dt}$$where N is the number of turns in the coil, \Phi_B is the magnetic flux through the coil, and t is time.At the moment that the normal to the plane of the coil is perpendicular to the magnetic field, the magnetic flux through the coil is zero. Therefore, the instantaneous emf in the coil is also zero.

A 420-Turn Circular Coil with an Area of 0