A ray of light is incident on the mid-point of a glass prism surface at an angle of 24.0° with the normal.For the glass,n = 1.55,and the prism apex angle is 44.3°.What is the angle of refraction as the ray enters the air on the far side of the prism?
A)0.853°
B)48.9°
C)18.3°
D)11.7°
E)29.1°

Question

Quizplus · Accepted Answer

We can use Snell's law to solve this problem:

n1*sin(θ1) = n2*sin(θ2)

where n1 and θ1 are the refractive index and angle of incidence in the glass prism, n2 and θ2 are the refractive index and angle of refraction in the air.

First, we need to find the angle of incidence in the prism.

θ1 = 90° - 44.3°/2 - 24.0° = 31.8°

Next, we can use Snell's law to find the angle of refraction in the air:

1.55*sin(31.8°) = sin(θ2)

θ2 = sin^-1(1.55*sin(31.8°)) = 48.9°

Therefore, the angle of refraction as the ray enters the air on the far side of the prism is 48.9°.

The correct answer is B.

A Ray of Light Is Incident on the Mid-Point of a Glass