A human body transports heat energy from the interior tissues,at temperature 37.0 $\circ$ C,to the skin surface at temperature 27.0 $\circ$ C,at a rate of 100 W.If the skin area is 1.5 m² and its thickness is 3.0 mm,what is the effective thermal conductivity of skin?

Question

Quizplus · Accepted Answer

The effective thermal conductivity ($k$) of the skin can be calculated using the formula for heat transfer: $Q = \frac{kA(T_{hot} - T_{cold})}{d}$, where $Q$ is the rate of heat transfer (100 W), $A$ is the area through which heat is transferred (1.5 $m^2$), $T_{hot} - T_{cold}$ is the temperature difference (37°C - 27°C = 10°C), and $d$ is the thickness of the skin (3.0 mm = 0.003 m). Rearranging the formula to solve for $k$ gives $k = \frac{Qd}{A(T_{hot} - T_{cold})}$. Substituting the given values yields $k = \frac{100 \times 0.003}{1.5 \times 10} = 0.020$ W/(m·K).

A Human Body Transports Heat Energy from the Interior Tissues,at ∘\circ∘

A Human Body Transports Heat Energy from the Interior Tissues,at $\circ$